Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

sudah sya googling pake solusi
semacam
if ($query_tampilkan === FALSE) {
die(mysql_error());
}

atau
if (false === $tampil) {
echo mysql_error();
}
Tetep saja sama,, data tidak tampil..

ini script saya,, mohon bantuan ya Gan suhu,, maklum ane newbie..
======
$tampil = mysql_query("SELECT * FROM poin, karyawanbmt WHERE poin.nik=karyawanbmt.nik ORDER BY kdpoin limit $posisi,$batas");

$no=$posisi+1;
while ($r=mysql_fetch_array($tampil)){
echo "<tr>
<td>$no</td>
<td>$r[nama]</td>
<td>$r[poin1]</td>
<td>$r[poin2]</td>
<td>$r[poin3]</td>
<td>$r[poin4]</td>
<td>$r[poin5]</td>
<td>$r[poin6]</td>
<td>$r[poin7]</td>
<td>$r[poin8]</td>
<td>$r[rekom]</td>
<td>$r[bulan]</td>
<td>$r[tahun]</td>
<td><a ><i class='icon2-file'></i> </a> 
<a ><i class='icon2-cancel-circle'></i></a>
</td>
</tr>";
$no++;
}
====
sya sengaja pake xammp versi lama,,