jadi begini ceritanya gan. ane lagi mau submit value dropdown menu kedalam database tapi dalam bentuk "addrow" ane nga berhasil nemu gan. uda google jg nga nemu.. tolong bantu ane dong.
<?php
session_start();
require_once('Connections/koneksi.php');
if($_REQUEST['submit'] == "Submit")
{
$name = $_POST["user"];
$masukdatabase = "INSERT INTO `com`(`user`) Values('$ame')";
}
?>
<html>
<head>
[removed]
function addRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
var colCount = table.rows[0].cells.length;
for(var i=0; i<colCount; i++) {
var newcell = row.insertCell(i);
newcell[removed] = table.rows[0].cells[i][removed];
switch(newcell.childNodes[0].type) {
case "text":
newcell.childNodes[0].value = "";
break;
case "checkbox":
newcell.childNodes[0].checked = false;
break;
case "select-one":
newcell.childNodes[0].selectedIndex = 0;
break;
}
}
}
function deleteRow(tableID) {
try {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
for(var i=0; i<rowCount; i++) {
var row = table.rows[i];
var chkbox = row.cells[0].childNodes[0];
if(null != chkbox && true == chkbox.checked) {
if(rowCount <= 1) {
alert("Cant delete all rows");
break;
}
table.deleteRow(i);
rowCount--;
i--;
}
}
}catch(e) {
alert(e);
}
}
[removed]
</head>
<body>
<form name="form1" method="post" action="adduser.php">
<table id="dataTable" width="auto" style="margin:-4px 0 0 0;" cellspacing="0px">
<tr>
<td style="width:20px;"><INPUT type="checkbox" name="chk" /></td>
<td><select name="user" id="user">
<option value="tono">tono</option>
<option value="tini">tini</option>
</select></td>
</tr>
</table>
<INPUT type="button" value="Add row">
<INPUT type="button" value="Delete row">
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
