<?php
session_start();
include "koneksi.php";
$username=$_POST['username'];
$password=$_POST['password'];
$query=mysql_query("select * from users where username='$username' and password='$password'");
$cek=mysql_num_rows($query);
if($cek){
$nama = $nama;
?>[removed]alert('Anda berhasil login');
document.location='tampil_user.php'[removed]<?php
} else {
?>[removed]alert('Username & Password Salah');
document.location='formlog.php'[removed]<?php
}
?>
Spoiler for tampil_user:
<html>
<head>
<title></title>
</head>
<body>
<?php
$sambung = mysql_connect("localhost", "root", "") or die ("Gagal konek ke server.");
mysql_select_db("iconstoc_nenkin99") or die ("Gagal membuka database.");
?>
<p align="left"> Data member <a href="logout.php">Logout</a></p>
<table border="1" align="left">
<tr align="left">
<th>Nama Sesuai Paspor</th>
<th>TTL</th>
<th>Alamat Sekarang</th>
<th>No. Telepon</th>
<th>Tanggal Kepulangan</th>
<th>Alamat Terakhir di Jepang</th>
<th>Nama Perusahaan</th>
<th>Alamat Perusahaan</th>
<th>No. Pokok Nenkin</th>
<th>Nama Bank</th>
<th>No. Rekening</th>
<th>Nama Pemilik</th>
<th>Alamat Bank</th>
<th>Status</th>
</tr>
<?php
$query = ("SELECT * FROM member WHERE nama = 'nama' ");
$result = mysql_query($query, $sambung) or die("gagal melakukan query"); while ($buff = mysql_fetch_array($result)) {
mau tanya nih gan
gimana ya caranya nampilin data berdaserkan user yang sedang login?
udeh dicoba bolak-balik tp ttp aja gak keluar datanya dan gak ada pesan error