[ASK] PHP logic update upload file

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[ASK] PHP logic update upload file

kernel101

30-05-2013 08:57

[ASK] PHP logic update upload file

Misi agan2 ,ane mau tanya nih .
mau bikin scrip untuk update file upload ,jika form file nya ada maka file yg di database akan terupdate tapi jika form file nya tidak ada file makan ngga akan update database nya,
ane menggunakan 2 form file .

berikut potongan script nya :

Quote:

Code:



$id = $_POST['id'];

$file_name = $_FILES['images']['name'];

$foto = 'upload/'.$file_name;

$path = "../upload/".$file_name;



$file_name2 = $_FILES['images2']['name'];

$path2 = "../upload/".$file_name2;

$foto2 = 'upload/'.$file_name2;



if((move_uploaded_file($_FILES['images']['tmp_name'],$path)&& (move_uploaded_file($_FILES['images2']['tmp_name'],$path2)) {

$userr = "UPDATE `products` SET `images` = '$foto',`images2` = '$foto2' WHERE `id` = '$id'";

$result = mysql_query($userr) 

 or die('Query failed: '.mysql_error());

echo "berhasil";

echo "<meta http-equiv='Refresh' content='1; URL=data.php'/>";

}elseif(move_uploaded_file($_FILES['images']['tmp_name'],$path){

$userr = "UPDATE `products` SET `images` = '$foto' WHERE `id` = '$id'";

$result = mysql_query($userr) 

 or die('Query failed: '.mysql_error());

echo "berhasil";



echo "<meta http-equiv='Refresh' content='1; URL=data.php'/>";

}elseif(move_uploaded_file($_FILES['images2']['tmp_name'],$path2){

$userr = "UPDATE `products` SET `images2` = '$foto2' WHERE `id` = '$id'";

$result = mysql_query($userr) 

 or die('Query failed: '.mysql_error());

echo "berhasil";



echo "<meta http-equiv='Refresh' content='1; URL=data.php'/>";

}else{



echo "berhasil";

echo "<meta http-equiv='Refresh' content='1; URL=data.php'/>";



}

mohon pencerahannya gan,udah 1 hari 1 malem muter2 di logic ini aja emoticon-Cape d... (S)

Diubah oleh kernel101 30-05-2013 09:00

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